Given an array of integers, print each element in reverse order as a single line of space-separated integers

An array is a type of data structure that stores elements of the same type in a contiguous block of memory. In an array, , of size , each memory location has some unique index,  (where ), that can be referenced as  (you may also see it written as ).

Given an array, , of  integers, print each element in reverse order as a single line of space-separated integers.

Note: If you've already solved our C++ domain's Arrays Introduction challenge, you may want to skip this.

Input Format

The first line contains an integer,  (the number of integers in ).
The second line contains  space-separated integers describing .

Output Format

Print all  integers in  in reverse order as a single line of space-separated integers.

Sample Input

4
1 4 3 2

Sample Output

2 3 4 1

Solution:
#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int main(){
    int n; 
    scanf("%d",&n);
    int *arr = malloc(sizeof(int) * n);
    for(int arr_i = 0; arr_i < n; arr_i++){
       scanf("%d",&arr[arr_i]);
    }
    for (int arr_i = n - 1; arr_i >= 0; arr_i--)
        {
        printf("%d ", arr[arr_i]);
    }
    return 0;
}